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[问答]

请问怎么使用M24LR的能量收集模式

嗨,
我正在研究无线应用,我想使用M24LR的能量收集模式。我对最大收获电流有疑问。数据表提到6mA是最高值。是否有可能通过更强的磁场或更大的天线(我需要大约16mA)来增加这个值?芯片会处理更大的电流吗?或者,最大范围6mA是否仅高于能量收集输出变为活动的值?
我会感激任何帮助。
最好的祝福,
马修

#max-current #wireless #NFC#m24lr #energy-harvesting

以上来自于谷歌翻译


以下为原文




Hi,
I am working on wireless application and i would like to use energy harvesting mode of M24LR. I have a question about maximum harvested current. Datasheet is mentioning 6mA as the highest value. Is it possible to incrase this value by stronger magnetic field or bigger antenna (i need about 16mA)? Does the chip will handle bigger currents? Or maybe max range 6mA is only value above which energy harvesting output becomes active?
I would be grateful for any kind of help.
Best regards,
Mathew

#max-current #wireless #nfc #m24lr #energy-harvesting

回帖(1)

鲍淑君

2019-7-30 10:09:55
亲爱的马特乌斯,
数据表的6mA值是最大电流吸收,对于电压输出高于2.7V,在ISO15693定义的条件下,最大场功率为7A / m,天线尺寸为72mm * 42mm。
我可以使用更大的天线或降低输出电压值来吸收更多电流(可能小于9mA)。但是不可能从M24LR器件中获得16mA的电流。
最好的祝福。

以上来自于谷歌翻译


以下为原文




Dear Mateusz,
The 6mA value of the datasheet is the maximum current sink, for a voltage output above 2.7V, in the conditions defined by ISO15693, which are a maximum field power of 7A/m, and an antenna size of 72mm*42mm.
I may be possible to sink more current (probably less than 9mA), with a bigger antenna, or by decreasing the output voltage value. But it will not be possible to achieve 16mA out of the M24LR device.
Best regards.
举报

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